## Friday, April 15, 2011

### Data Handling (Mean from Frequency Table)

How to calculate Mean from Frequency Table

A. The process
Refer to the following link for information on the process.

B. Notation

B. Question:

source: http://www.mathsisfun.com

1. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

2. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

=2.5454545

3. x̄ = ∑fx= [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 113/55

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5. mode=∑ƒx÷∑ƒ=[15(1)+27(2)+8(3)+5(4)]/[15+27+8+5]
=113/55
=2.054545454...

6. x̄=∑ƒx÷∑ƒ
=[15(1)+27(2)+8(3)+5(4)]÷(15+27+8+5)
=113/55
2.05454545...

7. \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
1(15) + 2(27) + 3(8) + 4(5)
---------------------------
15+27+8+5

= 15+54+24+20
-----------
55

= 113
-----
55

= 2.0545454545454545454545...
//////////////////////////////////////////////////

8. x̄ = ∑fx / ∑f = [15(1)+27(2)+8(3)+5(4)]/(15+27+8+5) = 113 / 55 ≈ 2.055

9. The Mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55 OR 2.054...

10. x̄ = ∑fx = [ 15 (1) + 27 (2)+8 (3) + 5 (4) ] ÷ (15 + 27 + 8 + 5) = 113 ÷ 55 ≈ 2.054...

11. x̄ = ∑fx/∑f=[1(15)+2(27)+3(8)+4(5)]/15+27+8+5=113/55=2.05 (rounded off)

12. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

13. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

14. mode is ∑fx/ ∑f= (15X1)+(2X27)+(3X8)+(4X5)/(15+27+8+5)=2 3/55 or 2.05~

15. x̄ = ∑fx÷∑f = [ (1x15 )+( 2x27 )+( 3x8 )+( 4x5 )]÷[ 15+27+8+5 ] = 2 3/55

16. x̄=∑fx÷∑f=[(15×1)+(2x27)+(3×8)+(4×5)] / (15+27+8+5)=2 and 3/55= 2.05

17. Mean number of parking spaces = ∑fx÷∑f = [15(1)+27(2)+8(3)+5(4)]/[15+27+8+5]= 2.045... (irrational number)