Friday, April 15, 2011

Data Handling (Mean from Frequency Table)

How to calculate Mean from Frequency Table

A. The process
Refer to the following link for information on the process.

B. Notation 



B. Question:
Please post your answer to the following question. Show your working clearly.


source: http://www.mathsisfun.com

17 comments:

  1. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

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  2. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

    =2.5454545

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  3. x̄ = ∑fx= [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 113/55

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  4. This comment has been removed by the author.

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  5. mode=∑ƒx÷∑ƒ=[15(1)+27(2)+8(3)+5(4)]/[15+27+8+5]
    =113/55
    =2.054545454...

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  6. x̄=∑ƒx÷∑ƒ
    =[15(1)+27(2)+8(3)+5(4)]÷(15+27+8+5)
    =113/55
    2.05454545...

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  7. \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
    1(15) + 2(27) + 3(8) + 4(5)
    ---------------------------
    15+27+8+5



    = 15+54+24+20
    -----------
    55


    = 113
    -----
    55

    = 2.0545454545454545454545...
    //////////////////////////////////////////////////

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  8. x̄ = ∑fx / ∑f = [15(1)+27(2)+8(3)+5(4)]/(15+27+8+5) = 113 / 55 ≈ 2.055

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  9. The Mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55 OR 2.054...

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  10. x̄ = ∑fx = [ 15 (1) + 27 (2)+8 (3) + 5 (4) ] ÷ (15 + 27 + 8 + 5) = 113 ÷ 55 ≈ 2.054...

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  11. x̄ = ∑fx/∑f=[1(15)+2(27)+3(8)+4(5)]/15+27+8+5=113/55=2.05 (rounded off)

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  12. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

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  13. mode = ∑fx÷∑f = [(1x15)+(2x27)+(3x8)+(4x5)]÷[15+27+8+5] = 2 3/55

    ReplyDelete
  14. mode is ∑fx/ ∑f= (15X1)+(2X27)+(3X8)+(4X5)/(15+27+8+5)=2 3/55 or 2.05~

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  15. x̄ = ∑fx÷∑f = [ (1x15 )+( 2x27 )+( 3x8 )+( 4x5 )]÷[ 15+27+8+5 ] = 2 3/55

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  16. x̄=∑fx÷∑f=[(15×1)+(2x27)+(3×8)+(4×5)] / (15+27+8+5)=2 and 3/55= 2.05

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  17. Mean number of parking spaces = ∑fx÷∑f = [15(1)+27(2)+8(3)+5(4)]/[15+27+8+5]= 2.045... (irrational number)

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